pub struct DirEntry(_);
Expand description
Entries returned by the ReadDir
iterator.
An instance of DirEntry
represents an entry inside of a directory on the
filesystem. Each entry can be inspected via methods to learn about the full
path or possibly other metadata through per-platform extension traits.
Implementations
Returns the full path to the file that this entry represents.
The full path is created by joining the original path to read_dir
with the filename of this entry.
Examples
use std::fs;
fn main() -> std::io::Result<()> {
for entry in fs::read_dir(".")? {
let dir = entry?;
println!("{:?}", dir.path());
}
Ok(())
}
RunThis prints output like:
"./whatever.txt"
"./foo.html"
"./hello_world.rs"
The exact text, of course, depends on what files you have in .
.
Returns the metadata for the file that this entry points at.
This function will not traverse symlinks if this entry points at a
symlink. To traverse symlinks use fs::metadata
or fs::File::metadata
.
Platform-specific behavior
On Windows this function is cheap to call (no extra system calls
needed), but on Unix platforms this function is the equivalent of
calling symlink_metadata
on the path.
Examples
use std::fs;
if let Ok(entries) = fs::read_dir(".") {
for entry in entries {
if let Ok(entry) = entry {
// Here, `entry` is a `DirEntry`.
if let Ok(metadata) = entry.metadata() {
// Now let's show our entry's permissions!
println!("{:?}: {:?}", entry.path(), metadata.permissions());
} else {
println!("Couldn't get metadata for {:?}", entry.path());
}
}
}
}
RunReturns the file type for the file that this entry points at.
This function will not traverse symlinks if this entry points at a symlink.
Platform-specific behavior
On Windows and most Unix platforms this function is free (no extra
system calls needed), but some Unix platforms may require the equivalent
call to symlink_metadata
to learn about the target file type.
Examples
use std::fs;
if let Ok(entries) = fs::read_dir(".") {
for entry in entries {
if let Ok(entry) = entry {
// Here, `entry` is a `DirEntry`.
if let Ok(file_type) = entry.file_type() {
// Now let's show our entry's file type!
println!("{:?}: {:?}", entry.path(), file_type);
} else {
println!("Couldn't get file type for {:?}", entry.path());
}
}
}
}
Run